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Question
Answer the following question.
What is the basic structural difference between glucose and fructose?
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Solution
Both Glucose and Fructose are hexose sugars with six carbon atoms but Glucose is an aldohexose and fructose is ketohexose which means the functional group present in glucose is an aldehyde and the functional group in fructose is a ketone.
\[\begin{array}{cc}
\phantom{..}\ce{O}\phantom{..}\ce{H}\phantom{.}\ce{OH}\phantom{.}\ce{OH}\phantom{}\\
\phantom{}||\phantom{...}|\phantom{...}|\phantom{...}|\phantom{.}\\
\ce{CH2OH-C-C-C-C-CH2OH}\\
\phantom{....}|\phantom{...}|\phantom{...}|\phantom{}\\
\phantom{....}\ce{HO}\phantom{..}\ce{H}\phantom{..}\ce{H}\phantom{..}\\
\text{D-fructose}
\end{array}\]
\[\begin{array}{cc}
\phantom{}\ce{OH}\phantom{..}\ce{H}\phantom{.}\ce{OH}\phantom{.}\ce{OH}\phantom{....}\\
\phantom{.}|\phantom{...}|\phantom{...}|\phantom{...}|\phantom{....}\\
\ce{CHO-C-C-C-C-CH2OH}\\
\phantom{}|\phantom{...}|\phantom{...}|\phantom{...}|\phantom{...}\\
\phantom{}\ce{H}\phantom{.}\ce{HO}\phantom{.}\ce{H}\phantom{..}\ce{H}\phantom{..}\\
\text{D-glucose}
\end{array}\]
RELATED QUESTIONS
How many moles of acetic anhydride will be required to form glucose pentaacetate from 2M of glucose?
(a) 2
(b) 5
(c) 10
(d) 2.5
Write the reaction involved when D-glucose is treated with the following reagent:
Br2 water
The following compound can be called as:

Acetylation of glucose yields ____________.
Glucose does not give Schiff’s test because of the formation of cyclic ____________.
The letter D and L in carbohydrates represent ____________.
Why does compound (A) given below not form an oxime?

(A)
Account for the following:
There are 5 OH groups in glucose
When D-glucose reacts with HI, it forms ______.
Give a reason for the following observations:
Penta-acetate of glucose does not react with hydroxylamine.
