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Question
An LPG cylinder can withstand a pressure of 14.9 atmospheres. The pressure gauge of the cylinder indicates 12 atmospheres at 27°C. Because of a sudden fire in the building, the temperature rises. At what temperature will the cylinder explode?
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Solution
P = 14.9 atm
V = 28 cm3
T = ?
P1 = 12 atm
V = V1
T1 = 300 K
Using gas equation,
`("P" "V")/"T" = ("P"_1 "V"_1)/"T"_1`
`(14.9xx"V")/"T" = (12xx"V")/300`
T = 372.5 K
T = 372.5 - 273 = 99.5 °C
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