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ABCD is a cyclic quadrilateral in which BA and CD when produced meet in E and EA = ED. Prove that  EB = EC. - Mathematics

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Question

ABCD is a cyclic quadrilateral in which BA and CD when produced meet in E and EA = ED. Prove that  EB = EC

Short/Brief Note
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Solution

 EB = EC

 Since, AD and BC are parallel to each other, so,

\[\angle ECB = \angle EDA \left( \text{ Corresponding angles }  \right)\]
\[\angle EBC = \angle EAD \left( \text{ Corresponding angles}  \right)\]
\[\text{ But } , \angle EDA = \angle EAD\]
\[\text{ Therefore } , \angle ECB = \angle EBC\]
\[ \Rightarrow EC = EB\]
\[ \text{ Therefore, }  \bigtriangleup \text{ ECB is an isosceles triangle }  .\]

 

 

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Chapter 15: Circles - Exercise 15.5 [Page 103]

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RD Sharma Mathematics [English] Class 9
Chapter 15 Circles
Exercise 15.5 | Q 26.2 | Page 103

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