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Question
A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 Nm. What minimum force must be applied on its rim?
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Solution
Given: Moment of force = 2.0 N m
Diameter = 2 m
So, radius = `"diameter"/2` = 1 m
Therefore, perpendicular distance d = radius = 1 m
Force f = ?
Moment of force = diameter × force
Force = `"moment of force"/"diameter"`
Force = `(2.0 Nm)/(1 m)`
Force = 2.0 N
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