Advertisements
Advertisements
प्रश्न
A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 Nm. What minimum force must be applied on its rim?
Advertisements
उत्तर
Given: Moment of force = 2.0 N m
Diameter = 2 m
So, radius = `"diameter"/2` = 1 m
Therefore, perpendicular distance d = radius = 1 m
Force f = ?
Moment of force = diameter × force
Force = `"moment of force"/"diameter"`
Force = `(2.0 Nm)/(1 m)`
Force = 2.0 N
APPEARS IN
संबंधित प्रश्न
How does the effect of force differ when it is applied on a non-rigid body?
State the effect of force F in of the following diagram.
State one way to decrease the moment of a given force about a given axis of rotation.
State two factor on which moment of force about a point depends.
State two factors affecting the turning effect of a force.
Write the expression for the moment of force about a given axis.
Define non-contact forces.
State when the moment of force is positive and when it is negative.
A nut is opened by a wrench of length 25 cm. If the least force required is 10 N, find the moment of force needed to turn the nut.
