Advertisements
Advertisements
प्रश्न
A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 Nm. What minimum force must be applied on its rim?
Advertisements
उत्तर
Given: Moment of force = 2.0 N m
Diameter = 2 m
So, radius = `"diameter"/2` = 1 m
Therefore, perpendicular distance d = radius = 1 m
Force f = ?
Moment of force = diameter × force
Force = `"moment of force"/"diameter"`
Force = `(2.0 Nm)/(1 m)`
Force = 2.0 N
APPEARS IN
संबंधित प्रश्न
What is the SI unit of the moment of force?
State one way to decrease the moment of a given force about a given axis of rotation.
The hand flour grinder is provided with a handle near the rim.
State Newton's first law of motion. Why is it called the law of inertia?
It is easier to turn the steering wheel of a large diameter than that of a small diameter. Given reason.
What is the work done when no net force is applied on the body?
A jack screw is provided with a long arm. Explain why?
State one factor on which the magnitude of a non-contact force depends. How does the magnitude of a non-contact force change along with distance?
What is meant by the term ‘moment of force’? If the moment of force is assigned a negative sign then will the turning tendency of the force be clockwise or anti-clockwise?
Assertion & Reasoning
- Assertion: The sum of the clockwise moments is equal to the sum of the anticlockwise moments.
- Reason: The principle of conservation of momentum is valid if the external force on the system is zero.
