Advertisements
Advertisements
प्रश्न
A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 Nm. What minimum force must be applied on its rim?
Advertisements
उत्तर
Given: Moment of force = 2.0 N m
Diameter = 2 m
So, radius = `"diameter"/2` = 1 m
Therefore, perpendicular distance d = radius = 1 m
Force f = ?
Moment of force = diameter × force
Force = `"moment of force"/"diameter"`
Force = `(2.0 Nm)/(1 m)`
Force = 2.0 N
APPEARS IN
संबंधित प्रश्न
To obtain a given moment of force for turning a body, the force needed can be decreased by
How does the effect of force differ when it is applied on a rigid body?
State one factor on which the magnitude of a non-contact force depends. How does it depend on the factor stated by you?.
State Newton's third law of motion.
The figure shows two forces each of magnitude 10 N acting at the point A and B at a separation of 50 cm, in opposite directions. Calculate the resultant moment of two forces about the point.
- A,
- B and
- O situated exactly at the middle of the two forces.
Classify the following amongst contact and non-contact forces.
Frictional force
Classify the following amongst contact and non-contact forces.
magnetic force
Define the moment of force.
Give an example for each of the following uses of a machine:
to change the point of application of force
The S.I. unit of moment of force is ______.
