Advertisements
Advertisements
Question
A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.
Advertisements
Solution
⊥ Distance = 10cm = 10/100 = 1/10 m
Force applied on spanner 5 N
∴ Moment of force = F ×⊥ distance
= 5 × 1/10 = 0.5 nm.
APPEARS IN
RELATED QUESTIONS
Match the column
| Column A | Column B |
| (a) Camel | (1) broad and deep foundation |
| (b) Truck | (2) broad feet |
| (c) Knife | (3) six or eight tyres |
| (d) High building | (4) sharp cutting edge |
| (e) Thrust | (5) atm |
| (f) Moment of force | (6) N |
| (g) Atmospheric pressure | (7) N m |
The hand flour grinder is provided with a handle near the rim.
Classify the following amongst contact and non-contact force.
force of tension in a string
A body X of mass 5 kg is moving with velocity 20 m s-2 while another body Y of mass 20 kg is moving with velocity 5 m S-1. Compare the momentum of the two bodies.
State two factor on which moment of force about a point depends.
Classify the following amongst contact and non-contact forces.
normal reaction force,
Classify the following amongst contact and non-contact forces.
electrostatic force
A wheel of diameter 3 m is shown in fig. 2 with axle at 0. A force F = 8 N is applied at Q in the direction shown in figure. Calculate the moment of force about:
(i) centre o, and
(ii) point p.


A metal rod AB of length 80 cm is balanced at 45 cm from the end A with 100 gf weights suspended from the two ends.
- If this rod is cut at the center, C, then compare the weight of AC to the weight of BC. (Use >, < or =)
- Give a reason for your answer in (a).
