Advertisements
Advertisements
Question
A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.
Advertisements
Solution
⊥ Distance = 10cm = 10/100 = 1/10 m
Force applied on spanner 5 N
∴ Moment of force = F ×⊥ distance
= 5 × 1/10 = 0.5 nm.
APPEARS IN
RELATED QUESTIONS
A force always produces both the linear and turning motions.
State the effect of force F in of the following diagram.
A wheel of diameter 2 m can be rotated about an axis passing through its center by a moment of force equal to 2.0 Nm. What minimum force must be applied on its rim?
Write an expression for the change in momentum of a body of mass m moving with velocity v if v << c.
State the relationship between force, mass and acceleration. Draw graphs showing the relationship between Acceleration and mass for a constant force.
A nut is opened by a wrench of length 10 cm. if the least force required is 5.0 N. find the moment of force needed to turn the nut.
Classify the following amongst contact and non-contact forces.
gravitation force
(i) What do you understand by the term couple of forces?
(ii) Calculate the moment of a couple shown in fig.
Write the expression for calculating the moment of force about a given point.
Clockwise moment produced by a force about a fulcrum is considered to be ______.
