Advertisements
Advertisements
Question
A nut is opened by a wrench of length 10 cm. if the least force required is 5.0 N. find the moment of force needed to turn the nut.
Advertisements
Solution
Length r = 10 cm = 0.1 m
F = 5N
Moment of force = F x r = 5 x 0.1 = 0.5 Nm
RELATED QUESTIONS
An effort is applied on the bigger wheel of a gear having 32 teeth. It is used to turn a wheel of 8 teeth. Where it is used.
Name the factors affecting the turning effect of a body
A force is applied on (i) a non-rigid body and (ii) a rigid body. How does the effect of the force differ in the above two cases?
On what factors does the effect of thrust on a surface depend?
Find the moment of force of 20 N about an axis of rotation at distance 0.5 m from the force.
A spanner (or wrench) has a long handle. Why?
The diagram shows two forces F1 = 5 N and F2 = 3N acting at point A and B of a rod pivoted at a point O, such that OA = 2m and OB = 4m

Calculate:
- Moment of force F1 about O
- Moment of force F2 about O
- Total moment of the two forces about O.
The diagram in the figure shows a uniform metre rule weighing 100 gf, pivoted as its centre O. two weight 150 gf and 250 gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm . Calculate
the total anticlockwise moment about o.

Calculate the magnitude of the force of a couple, when the arm of the couple is 63 cm and the moment of the couple is 21 Nm.
A nut is opened by a wrench of length 25 cm. If the least force required is 10 N, find the moment of force needed to turn the nut.
