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Karnataka Board PUCPUC Science Class 11

A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m.

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Question

A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in ______.

Options

  • one second

  • 0.5 second

  • 2 seconds

  • data given is insufficient

MCQ
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Solution

A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in 0.5 second.

Explanation:


Mass m = 2.5 kg

μ = Mass per unit length

= `m/l`

= `(2.5  kg)/20`

= `125/10`

= 0.125 kg/m

Speed `v = sqrt(T/μ)`

= `sqrt(200/0.125)`  ......[Speed of transverse waves in any string]

`l = v xx t`

⇒ `20 = sqrt(200/0.125) xx t`

⇒ `t = 20 xx sqrt(125/(2 xx 10^5)`

= `20 xx sqrt((25 xx 5)/(2 xx 10^5))`

= `20 xx sqrt(25 xx 1/(0.4 xx 10^5))`

= `20 xx 5 sqrt(1/(4 xx 10^4))`

= `(20 xx 5)/(2 xx 10^2)`

= `1/2`

= 0.5

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Chapter 15: Waves - Exercises [Page 107]

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NCERT Exemplar Physics Exemplar [English] Class 11
Chapter 15 Waves
Exercises | Q 15.9 | Page 107

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