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A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m.

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प्रश्न

A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in ______.

विकल्प

  • one second

  • 0.5 second

  • 2 seconds

  • data given is insufficient

MCQ
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उत्तर

A string of mass 2.5 kg is under a tension of 200 N. The length of the stretched string is 20.0 m. If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in 0.5 second.

Explanation:


Mass m = 2.5 kg

μ = Mass per unit length

= `m/l`

= `(2.5  kg)/20`

= `125/10`

= 0.125 kg/m

Speed `v = sqrt(T/μ)`

= `sqrt(200/0.125)`  ......[Speed of transverse waves in any string]

`l = v xx t`

⇒ `20 = sqrt(200/0.125) xx t`

⇒ `t = 20 xx sqrt(125/(2 xx 10^5)`

= `20 xx sqrt((25 xx 5)/(2 xx 10^5))`

= `20 xx sqrt(25 xx 1/(0.4 xx 10^5))`

= `20 xx 5 sqrt(1/(4 xx 10^4))`

= `(20 xx 5)/(2 xx 10^2)`

= `1/2`

= 0.5

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अध्याय 15: Waves - Exercises [पृष्ठ १०७]

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एनसीईआरटी एक्झांप्लर Physics Exemplar [English] Class 11
अध्याय 15 Waves
Exercises | Q 15.9 | पृष्ठ १०७

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