हिंदी

The string of a guitar is 80 cm long and has a fundamental frequency of 112 Hz. If a guitarist wishes to produce a frequency of 160 Hz, where should the person press the string?

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प्रश्न

The string of a guitar is 80 cm long and has a fundamental frequency of 112 Hz. If a guitarist wishes to produce a frequency of 160 Hz, where should the person press the string?

संख्यात्मक
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उत्तर

Given: L1 = 80 cm

n1 = 112 Hz

n2 = 160 Hz

According to the law of length:

n1L1 = n2L2

L2 = `(n_1 L_1)/n_2`

= `(112 (80))/160`

= 56 cm

∴ The guitarist must press the string so that the vibrating length becomes 56 cm.

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अध्याय 6: Superposition of Waves - Exercises [पृष्ठ १५७]

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बालभारती Physics [English] Standard 12 Maharashtra State Board
अध्याय 6 Superposition of Waves
Exercises | Q 24. | पृष्ठ १५७

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