हिंदी

A string 1 m long is fixed at one end. The other end is moved up and down with a frequency of 20 Hz. Due to this, a stationary wave with four complete loops gets produced on the string.

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प्रश्न

A string 1 m long is fixed at one end. The other end is moved up and down with a frequency of 20 Hz. Due to this, a stationary wave with four complete loops gets produced on the string. Find the speed of the progressive wave which produces the stationary wave. 

योग
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उत्तर

L = 1 m, n = 20 Hz

Since an antinode is formed at the free end.

Thus, with four and a half loops of the string,

L = `λ/4 + 2λ = 9/4λ`

∴ λ = `(4"L")/9 = 4/9 xx 1 = 4/9`m

∴ v = nλ

= `20 xx 4/9`

= 8.88 m/s

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अध्याय 6: Superposition of Waves - Very Short Answer

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एससीईआरटी महाराष्ट्र Physics [English] 12 Standard HSC
अध्याय 6 Superposition of Waves
Very Short Answer | Q 13

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