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Karnataka Board PUCPUC Science Class 11

A 200 Hz Wave with Amplitude 1 Mm Travels on a Long String of Linear Mass Density 6 G M−1 Kept Under a Tension of 60 N. (A) Find the Average Power Transmitted

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Question

A 200 Hz wave with amplitude 1 mm travels on a long string of linear mass density 6 g m−1 kept under a tension of 60 N. (a) Find the average power transmitted across a given point on the string. (b) Find the total energy associated with the wave in a 2⋅0 m long portion of the string.

Sum
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Solution

Given,
Frequency of the wave, f = 200 Hz
Amplitude, A = 1 mm = 10−3 m
Linear mass density, m = 6 gm−3
Applied tension, T = 60 N
Now,
Let the velocity of the wave be v.
Thus, we have:

\[v = \sqrt{\left( \frac{T}{m} \right)} = \sqrt{\frac{\left( 60 \right)}{\left( 6 \times {10}^{- 3} \right)}}\] 

\[ =  {10}^2  = 100  m/s\]
(a) Average power is given as 

\[P_{average}  = 2 \pi^2 m\nu A^2  f^2 \] 

\[= 2 \times  \left( 3 . 14 \right)^2  \times \left( 6 \times {10}^{- 3} \right) \times 100 \times \left( {10}^{- 3} \right) \times  {200}^2 \] 

\[  = 473 \times  {10}^{- 3}  = 0 . 47  W\] 
(b) Length of the string = 2 m
Time required to cover this distance:

\[t = \frac{2}{100} = 0 . 02  s\] 

\[Energy = Power \times t\] 

\[ = 0 . 47 \times 0 . 02\] 

\[ = 9 . 4 \times  {10}^{- 3}   J = 9 . 4  mJ\]

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Chapter 15: Wave Motion and Waves on a String - Exercise [Page 325]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 15 Wave Motion and Waves on a String
Exercise | Q 29 | Page 325

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