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Karnataka Board PUCPUC Science Class 11

A rod of length l and negligible mass is suspended at its two ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths (Figure). - Physics

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Question

A rod of length l and negligible mass is suspended at its two ends by two wires of steel (wire A) and aluminium (wire B) of equal lengths (Figure). The cross-sectional areas of wires A and B are 1.0 mm2 and 2.0 mm2, respectively.

(YAl = 70 × 109 Nm−2 and Ysteel = 200 × 109 Nm–2)

  1. Mass m should be suspended close to wire A to have equal stresses in both the wires.
  2. Mass m should be suspended close to B to have equal stresses in both the wires.
  3. Mass m should be suspended at the middle of the wires to have equal stresses in both the wires.
  4. Mass m should be suspended close to wire A to have equal strain in both wires.
Short/Brief Note
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Solution

b and d

Explanation:

Let the mass is placed at x from the end B.


Let TA and TB be the tensions in wire A and wire B respectively.

For the rotational equilibrium of the system,

∑τ = 0  ......(Total torque = 0)

⇒ `T_Bx = T_A (l - x)` = 0

⇒ `T_B/T_A = (l - x)/x`  ......(i)

Stress in wire `A = S_A = T_A/a_A`

Stress in wire `B = S_B = T_B/a_B`

Where aA and aB are cross-sectional areas of wire A and B respectively.

By question aB = 2aA

Now, for equal stress SA = SB 

⇒ `T_A/a_A = T_B/a_B`

⇒ `T_B/T_A = a_B/a_A` = 2

⇒ `(l - x)/x` = 2

⇒ `l/x - 1` = 2

⇒ `x = l/3`

⇒ `l - x = l - l/3 = (2l)/3`

Hence, mass m should be placed closer to B.

For equal train, (strain)A = (strain)B

⇒ `(Y_A)/S_A = Y_B/S_B` ......(Where YA and YB are Young moduli)

⇒ `Y_(steel)/(T_A/a_A) = Y_(Al)/(T_B/a_B)`

⇒ `Y_(steel)/Y_(Al) = T_A/T_B xx a_B/a_A = (x/(l - x))((2a_A)/a_A)`

⇒ `(200 xx 10^9)/(70 xx 10^9) = (2x)/(l - x)`

⇒ `20/7 = (2x)/(l - x)`

⇒ `10/7 = x/(l - x)`

⇒ `10l - 10x = 7x`

⇒ `17x = 10l`

⇒ `x = (10l)/17`

`l - x = l - (10l)/17 = (7l)/17`

Hence, mass m should be placed closer to wire A.

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Chapter 9: Mechanical Properties of Solids - Exercises [Page 68]

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NCERT Exemplar Physics [English] Class 11
Chapter 9 Mechanical Properties of Solids
Exercises | Q 9.11 | Page 68

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