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Question
Two strips of metal are riveted together at their ends by four rivets, each of diameter 6.0 mm. What is the maximum tension that can be exerted by the riveted strip if the shearing stress on the rivet is not to exceed 6.9 × 107 Pa? Assume that each rivet is to carry one-quarter of the load.
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Solution 1
Diameter of the metal strip, d = 6.0 mm = 6.0 × 10–3 m
Radius, `r = d/2 = 3.0 xx 10^(-3)m`
Maximum shearing stress = 6.9 × 107 Pa
`"Maximum stress" = "Maximum load or force"/"Area"`
Maximum force = Maximum stress × Area
= 6.9 × 107 × π × (r) 2
= 6.9 × 107 × π × (3 ×10–3)2
= 1949.94 N
Each rivet carries one quarter of the load.
∴ Maximum tension on each rivet = 4 × 1949.94 = 7799.76 N
Solution 2
Diameter = 6mm; Radius, r = 3 x 10-3 m;
Maximum stress = 6.9 x 107 Pa
Maximum load on a rivet
= Maximum stress x cross-sectional area
= 6.9 x 107 x 22/7 (3 x 10-3)2 N = 1952 N
Maximum tension = 4 x 1951.7 N = 7.8 x 103 N.
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Answer in one sentence.
How should be a force applied on a body to produce shearing stress?
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