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Karnataka Board PUCPUC Science Class 11

A wire is suspended from the ceiling and stretched under the action of a weight F suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight.

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Question

A wire is suspended from the ceiling and stretched under the action of a weight F suspended from its other end. The force exerted by the ceiling on it is equal and opposite to the weight.

  1. Tensile stress at any cross section A of the wire is F/A.
  2. Tensile stress at any cross section is zero.
  3. Tensile stress at any cross section A of the wire is 2F/A.
  4. Tension at any cross section A of the wire is F.
Short/Brief Note
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Solution

a and d

Explanation:

According to the diagram, a wire is stretched under the j action of a weight F suspended from its other end.

Clearly, the force at each cross-section is F.

Now applying the formula,

Tensile stress = Force applied/Area of cross-section = F/A

Tension = Applied force = F

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Chapter 9: Mechanical Properties of Solids - Exercises [Page 68]

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NCERT Exemplar Physics [English] Class 11
Chapter 9 Mechanical Properties of Solids
Exercises | Q 9.10 | Page 68

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