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A problem in Mathematics is given to three students whose chances of solving it are 12,13,14 respectively. If the events of their solving the problem are independent then the probability

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Question

A problem in Mathematics is given to three students whose chances of solving it are `1/2, 1/3, 1/4` respectively. If the events of their solving the problem are independent then the probability that the problem will be solved, is ______.

Options

  • `1/4`

  • `1/3`

  • `1/2`

  • `3/4`

MCQ
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Solution 1

A problem in Mathematics is given to three students whose chances of solving it are `1/2, 1/3, 1/4` respectively. If the events of their solving the problem are independent then the probability that the problem will be solved, is `underlinebb(3/4)`.

Explanation:

Let A, B, C be the respective events of solving the problem.

Then, P(A) = `1/2`, P(B) = `1/3` and P(C) = `1/4`.

Here, A, B, C are independent events.

Problem is solved if at least one of them solves the problem.

Required probability is

= P(A ∪ B ∪ C)

= `1 - P(overlineA)P(overlineB)P(overlineC)`

= `1 - (1 - 1/2)(1 - 1/3)(1 - 1/4)`

= `1 - 1/4`

= `3/4`.

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Solution 2

A problem in Mathematics is given to three students whose chances of solving it are `1/2, 1/3, 1/4` respectively. If the events of their solving the problem are independent then the probability that the problem will be solved, is `underlinebb(3/4)`.

Explanation:

The problem will be solved if one or more of them can solve the problem.

The probability is

`P(Aoverline(BC)) + P(overlineABoverlineC) + P(overline(AB)C) + P(ABoverlineC) + P(AoverlineBC) + P(overlineABC) + P(ABC)`

= `1/2. 2/3. 3/4 + 1/2. 1/3. 3/4 + 1/2 . 2/3. 1/4 + 1/2. 1/3. 3/4 + 1/2. 2/3. 1/4 + 1/2. 1/3. 1/4 + 1/2. 1/3. 1/4`

= `3/4`.

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Solution 3

A problem in Mathematics is given to three students whose chances of solving it are `1/2, 1/3, 1/4` respectively. If the events of their solving the problem are independent then the probability that the problem will be solved, is `underlinebb(3/4)`.

Explanation:

Let us think quantitively.

Let us assume that there are 100 questions given to A.

A solves `1/2 xx 100` = 50 questions then remaining 50 questions is given to B and B solves `50 xx 1/3` = 16.67 questions.

Remaining `50 xx 2/3` questions is given to C and C solves `50 xx 2/3 xx 1/4` = 8.33 questions.

Therefore, number of questions solved is 50 + 16.67 + 8.33 = 75.

So, required probability is `75/100 = 3/4`.

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