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A bag contains 3 red and 5 white balls. Two balls are drawn at random one after the other without replacement. Find the probability that both the balls are white. - Mathematics and Statistics

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Question

A bag contains 3 red and 5 white balls. Two balls are drawn at random one after the other without replacement. Find the probability that both the balls are white.

Solution: Let,

A : First ball drawn is white

B : second ball drawn in white.

P(A) = `square/square`

After drawing the first ball, without replacing it into the bag a second ball is drawn from the remaining `square` balls.

∴ P(B/A) = `square/square`

∴ P(Both balls are white) = P(A ∩ B)

`= "P"(square) * "P"(square)`

`= square * square`

= `square`

Sum
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Solution

Let, A: First ball drawn is white

B: Second ball drawn is white.

P(A) = `underline(5/8)`

After drawing the first ball, without replacing it into the bag a second ball is drawn from the remaining 7 balls.

∴ `"P"("B"//"A")` = `underline(4/7)`

∴ P(Both balls are white) = P(A ∩ B)

= `"P"underline(("A")) * "P"underline(("B"//"A"))`

= `underline(5/8) . underline(4/7)`

= `underline(5/14)`

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Chapter 9: Probability - Exercise 9.3 [Page 206]

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