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Karnataka Board PUCPUC Science Class 11

A particle starting from rest moves with constant acceleration. If it takes 5.0 s to reach the speed 18.0 km/h find the distance travelled by the particle during this period.

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Question

A particle starting from rest moves with constant acceleration. If it takes 5.0 s to reach the speed 18.0 km/h find the distance travelled by the particle during this period.

Short/Brief Note
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Solution

Initial velocity of the particle, u = 0
Final velocity of the particle, v = 18 km/h = 5 m/s
Time, t = 5 s
Acceleration, a = (v − u)/t
⇒ a = (5 − 0)/5 = 1 m/s2
Distance,

\[s = \text{ut } + \frac{1}{2}\text{ at}^2\]
\[\Rightarrow s = \frac{1}{2} \times 1 \times \left( 5 \times 5 \right) = 12 . 5 \text{ m } \]
 Distance travelled, s = 12.5 m

 

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Chapter 3: Rest and Motion: Kinematics - Exercise [Page 52]

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HC Verma Concepts of Physics Volume 1 and 2 [English]
Chapter 3 Rest and Motion: Kinematics
Exercise | Q 18.2 | Page 52

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