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A particle starting from rest moves with constant acceleration. If it takes 5.0 s to reach the speed 18.0 km/h find the distance travelled by the particle during this period.

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प्रश्न

A particle starting from rest moves with constant acceleration. If it takes 5.0 s to reach the speed 18.0 km/h find the distance travelled by the particle during this period.

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उत्तर

Initial velocity of the particle, = 0
Final velocity of the particle, = 18 km/h = 5 m/s
Time, t = 5 s
Acceleration, a = (v − u)/t
⇒ a = (5 − 0)/5 = 1 m/s2
Distance,

\[s = \text{ut } + \frac{1}{2}\text{ at}^2\]
\[\Rightarrow s = \frac{1}{2} \times 1 \times \left( 5 \times 5 \right) = 12 . 5 \text{ m } \]
 Distance travelled, s = 12.5 m

 

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पाठ 3: Rest and Motion: Kinematics - Exercise [पृष्ठ ५२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 3 Rest and Motion: Kinematics
Exercise | Q 18.2 | पृष्ठ ५२

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