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A ball is projected vertically upward with a speed of 50 m/s. Find the maximum height.

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प्रश्न

A ball is projected vertically upward with a speed of 50 m/s. Find the maximum height. 

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उत्तर

Given:
Initial speed of the ball, u = 50 m/s
Acceleration, a = −10 m/s2
At the highest point, velocity of the ball is 0. 

\[s = \frac{v^2 - u^2}{2a}\]
   ⇒\[s = \frac{\left( 0^2 - {50}^2 \right)}{2 \times \left( - 10 \right)} = 125 \text{ m } \]

Maximum height = 125 m

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पाठ 3: Rest and Motion: Kinematics - Exercise [पृष्ठ ५२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 3 Rest and Motion: Kinematics
Exercise | Q 23.1 | पृष्ठ ५२

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