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A ball is thrown horizontally from a point 100 m above the ground with a speed of 20 m/s. Find the time it takes to reach the ground .

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प्रश्न

A ball is thrown horizontally from a point 100 m above the ground with a speed of 20 m/s. Find the time it takes to reach the ground .

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उत्तर

Given:
Speed of the ball, ux = 20 m/s
Height from which the ball is dropped, h = 100 m

Let t be the time taken by the ball to reach the ground.
Using the equation of motion, we have:

\[h = u_y t + \frac{1}{2}g t^2\]

Here,
Acceleration of gravity, g = 9.8 ms−2
Vertical component of velocity, uy = 0

\[\therefore t = \sqrt{\left( \frac{2h}{g} \right)}\]

\[ \Rightarrow t = \sqrt{\frac{2 \times 100}{9 . 8}} = 4 . 5 s\]

Therefore, the time required by the ball to reach the ground is 4.5 seconds.

 

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पाठ 3: Rest and Motion: Kinematics - Exercise [पृष्ठ ५२]

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एचसी वर्मा Concepts of Physics Volume 1 and 2 [English]
पाठ 3 Rest and Motion: Kinematics
Exercise | Q 32.1 | पृष्ठ ५२

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