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Karnataka Board PUCPUC Science Class 11

A Ball is Projected Vertically Upward with a Speed of 50 M/S. Find the Time to Reach the Maximum Height .

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Question

A ball is projected vertically upward with a speed of 50 m/s. Find the time to reach the maximum height .

Short/Brief Note
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Solution

Given:
Initial speed of the ball, u = 50 m/s
Acceleration, a = −10 m/s2
At the highest point, velocity of the ball is 0.

\[t = \frac{\left( v - u \right)}{a} = \frac{\left( 0 - 50 \right)}{- 10} = 5 s\]

 

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Chapter 3: Rest and Motion: Kinematics - Exercise [Page 52]

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HC Verma Concepts of Physics Vol. 1 [English] Class 11 and 12
Chapter 3 Rest and Motion: Kinematics
Exercise | Q 23.2 | Page 52

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