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A hockey ball of mass 200 g travelling at 10 m s−1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s−1.

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Question

A hockey ball of mass 200 g travelling at 10 m s−1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 m s−1. Calculate the change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Numerical
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Solution

Mass of ball (m) = 200 g = 0.2 kg

Initial velocity of ball (u1) = 10 ms-1

∴ The initial momentum of the ball = mu1

= 0.2 kg × 10 ms-1

= 2 N s

Final velocity of ball (u2) = - 5 ms-1

(The minimum sign denotes that the ball is moving in the opposite direction.)

∴ Final momentum of ball = mu2

= 0.2 kg × (- 5 ms-1)

= - 1 N s

∴ Change in momentum = Final momentum - Initial momentum

= - 1Ns - 2Ns

= - 3Ns

The Minus sign denotes that the change in momentum is opposite to the direction of the initial momentum of the ball.

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Chapter 8: Force and Laws of Motion - Exercises [Page 98]

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NCERT Science [English] Class 9
Chapter 8 Force and Laws of Motion
Exercises | Q 12. | Page 98

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