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A Function F : R → R Is Defined As F(X) = X3 + 4. is It a Bijection Or Not? in Case It is a Bijection, Find F−1 (3).

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Question

A function f : R → R is defined as f(x) = x3 + 4. Is it a bijection or not? In case it is a bijection, find f−1 (3).

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Solution

Injectivity of f:
Let x and y be two elements of domain (R), such that

f (x) = f (y)

⇒ x3 + 4 = y3 + 4

⇒ x3 = y3

⇒ x = y

So, f is one-one.

Surjectivity of f:
Let y be in the co-domain (R), such that f(x) = y.

⇒  x2 + 4 = y 

⇒ x3 = y - 4

⇒ `x = 3sqrt( y-4) in R` (domain)

⇒ f is onto.
So, f is a bijection and, hence, is invertible.

Finding f  -1:

Let f−1 (x) = y              ...(1)

⇒ x = f (y)

⇒ x = y3+ 4

⇒ x − 4 = y3

⇒ `y = 3sqrt(x-4)`

So, f−1(x) = `3sqrt(x-4)`         [from (1)]

`f^-1(3) = 3sqrt(3-4) = 3sqrt-1 = -1`

 

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Chapter 2: Functions - Exercise 2.4 [Page 69]

APPEARS IN

R.D. Sharma Mathematics Volume 1 and 2 [English] Class 12
Chapter 2 Functions
Exercise 2.4 | Q 11 | Page 69

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