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Question
A computer centre has got three expert programmers. The centre needs three application programmes to be developed. The head of the computer centre, after studying carefully the programmes to be developed, estimates the computer time in minitues required by the experts to the application programme as follows.
| Programmers | ||||
| P | Q | R | ||
| Programmers | 1 | 120 | 100 | 80 |
| 2 | 80 | 90 | 110 | |
| 3 | 110 | 140 | 120 | |
Assign the programmers to the programme in such a way that the total computer time is least.
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Solution
Here the number of rows and columns are equal.
∴ The given assignment problem is balanced.
Step 1: Select the smallest element in each row and subtract this from all the elements in its row.
| Programmers | ||||
| P | Q | R | ||
| Programmers | 1 | 40 | 20 | 0 |
| 2 | 0 | 10 | 30 | |
| 3 | 0 | 30 | 10 | |
Step 2: Select the smallest element in each column and subtract this from all the elements in its column.
| Programmers | ||||
| P | Q | R | ||
| Programmers | 1 | 40 | 10 | 0 |
| 2 | 0 | 0 | 30 | |
| 3 | 0 | 20 | 10 | |
Step 3: Examine the rows with exactly one zero, mark the zero by □. Mark other zeros in its column by X.
| Programmers | ||||
| P | Q | R | ||
| Programmers | 1 | 40 | 10 | 0 |
| 2 | 0 | 0 | 30 | |
| 3 | 0 | 20 | 10 | |
Step 4: Now examine the columns with exactly one zero mark the zero by □.
Mark other zeros in its row by X.
| Programmers | ||||
| P | Q | R | ||
| Programmers | 1 | 40 | 10 | 0 |
| 2 | 0 | 0 | 30 | |
| 3 | 0 | 20 | 10 | |
Thus all the three assignment have been made.
The optimal assignment schedule and total cost is
| Programmers | Programmes | Cost |
| 1 | R | 80 |
| 2 | Q | 90 |
| 3 | P | 110 |
| Total Cost | 280 | |
The optimal assignment (minimum) cost = ₹ 280.
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RELATED QUESTIONS
Five different machines can do any of the five required jobs, with different profits resulting from each assignment as shown below:
| Job | Machines (Profit in ₹) | ||||
| A | B | C | D | E | |
| 1 | 30 | 37 | 40 | 28 | 40 |
| 2 | 40 | 24 | 27 | 21 | 36 |
| 3 | 40 | 32 | 33 | 30 | 35 |
| 4 | 25 | 38 | 40 | 36 | 36 |
| 5 | 29 | 62 | 41 | 34 | 39 |
Find the optimal assignment schedule.
The assignment problem is said to be balanced if ______.
Choose the correct alternative :
The assignment problem is said to be balanced if it is a ______.
Choose the correct alternative :
In an assignment problem if number of rows is greater than number of columns then
The objective of an assignment problem is to assign ______.
Choose the correct alternative:
The assignment problem is generally defined as a problem of ______
In an assignment problem if number of rows is greater than number of columns, then dummy ______ is added
Three jobs A, B and C one to be assigned to three machines U, V and W. The processing cost for each job machine combination is shown in the matrix given below. Determine the allocation that minimizes the overall processing cost.
| Machine | ||||
| U | V | W | ||
| Jobs | A | 17 | 25 | 31 |
| B | 10 | 25 | 16 | |
| C | 12 | 14 | 11 | |
(cost is in ₹ per unit)
Five wagons are available at stations 1, 2, 3, 4 and 5. These are required at 5 stations I, II, III, IV and V. The mileage between various stations are given in the table below. How should the wagons be transported so as to minimize the mileage covered?
| I | II | III | IV | V | |
| 1 | 10 | 5 | 9 | 18 | 11 |
| 2 | 13 | 9 | 6 | 12 | 14 |
| 3 | 7 | 2 | 4 | 4 | 5 |
| 4 | 18 | 9 | 12 | 17 | 15 |
| 5 | 11 | 6 | 14 | 19 | 10 |
A plant manager has four subordinates and four tasks to perform. The subordinates differ in efficiency and task differ in their intrinsic difficulty. Estimates of the time subordinate would take to perform tasks are given in the following table:
| I | II | III | IV | |
| A | 3 | 11 | 10 | 8 |
| B | 13 | 2 | 12 | 2 |
| C | 3 | 4 | 6 | 1 |
| D | 4 | 15 | 4 | 9 |
Complete the following activity to allocate tasks to subordinates to minimize total time.
Solution:
Step I: Subtract the smallest element of each row from every element of that row:
| I | II | III | IV | |
| A | 0 | 8 | 7 | 5 |
| B | 11 | 0 | 10 | 0 |
| C | 2 | 3 | 5 | 0 |
| D | 0 | 11 | 0 | 5 |
Step II: Since all column minimums are zero, no need to subtract anything from columns.
Step III: Draw the minimum number of lines to cover all zeros.
| I | II | III | IV | |
| A | 0 | 8 | 7 | 5 |
| B | 11 | 0 | 10 | 0 |
| C | 2 | 3 | 5 | 0 |
| D | 0 | 11 | 0 | 5 |
Since minimum number of lines = order of matrix, optimal solution has been reached
Optimal assignment is A →`square` B →`square`
C →IV D →`square`
Total minimum time = `square` hours.
