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Question
Find the optimal solution for the assignment problem with the following cost matrix.
| Area | |||||
| 1 | 2 | 3 | 4 | ||
| P | 11 | 17 | 8 | 16 | |
| Salesman | Q | 9 | 7 | 12 | 6 |
| R | 13 | 16 | 15 | 12 | |
| S | 14 | 10 | 12 | 11 | |
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Solution
Here the number of rows and columns are equal.
∴ The given assignment problem is balanced.
Step 1: Select the smallest element in each row and subtract this from all the elements in its row.
| Area | |||||
| 1 | 2 | 3 | 4 | ||
| P | 3 | 9 | 0 | 8 | |
| Salesman | Q | 3 | 1 | 6 | 0 |
| R | 1 | 4 | 3 | 0 | |
| S | 4 | 0 | 2 | 1 | |
Step 2: Select the smallest element in each column and subtract this from all the elements in its column.
| Area | |||||
| 1 | 2 | 3 | 4 | ||
| P | 2 | 9 | 0 | 8 | |
| Salesman | Q | 2 | 1 | 6 | 0 |
| R | 0 | 4 | 3 | 0 | |
| S | 3 | 0 | 2 | 1 | |
Step 3: (Assignment)
Examine the rows with exactly one zero. Mark the zero by □ Mark other zeros in its column by X
| Area | |||||
| 1 | 2 | 3 | 4 | ||
| P | 2 | 9 | 0 | 8 | |
| Salesman | Q | 2 | 1 | 6 | 0 |
| R | 0 | 4 | 3 | 0 | |
| S | 3 | 0 | 2 | 1 | |
Thus all the four assignments have been made.
The optimal assignment schedule and total cost.
| Salesman | Area | Cost |
| P | 3 | 8 |
| Q | 4 | 6 |
| R | 1 | 13 |
| S | 2 | 10 |
| Total | 37 | |
The Optimum cost (minimum) = ₹ 37
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