Advertisements
Advertisements
Question
A burner raises the temperature of 360 g of water from 40°C to 100°C in 5 minutes. Calculate the rate of heat supplied by the burner.
Advertisements
Solution
m = 360 g = O .36 kg
Change in temperature, ΔT = (100 - 40)°C = 60°C = 60 K
Amount of heat required, Q = m x C x ΔT
= 0.36 x 4200 x 60 = 90720 J
Time taken = 5 min = 300 sec
Rate of heat supplied = `"Q"/"t" = 90720/300` = 302.4 J/s
APPEARS IN
RELATED QUESTIONS
Write the expression for the heat energy Q received by the substance when m kg of substance of specific heat capacity c Jkg-1 k-1 is heated through Δt° C.
What impact will global warming have on the health of the affected population?
Study the following procedure and answer the questions below:
1. Take 3 spheres of iron, copper and lead of equal mass.
2. Put all the 3 spheres in boiling water in a beaker for some time.
3. Take 3 spheres out of the water. Put them immediately on a thick slab of wax.
4. Note, the depth that each sphere goes into the wax.
i) Which property of substance can be studied with this procedure?
ii) Describe that property in minimum words.
iii) Explain the rule of heat exchange with this property.
Water boils at 120 °C in a pressure cooker. Explain the reason.
State the condition for the flow of heat energy from one body to another.
Name the substance which has maximum specific heat capacity.
If substances A and B are liquids then which one would be more useful in car radiators?
Given: Specific heat capacity’A’ 3.8 J/g /K. Specific heat capacity ‘B’ 0.4 J/g /K.
All metals have the same specific heat capacity.
50 g of copper is heated to increase its temperature by 10° C. If the same quantity of heat is given to 5 g water, the rise in its temperature is [Specific heat of copper = 420 joule-kg-1 °C-1 , specific heat of water = 4200 joule-kg-I °C-1]
At same temperature and pressure of an ideal gas, ____________.
