Advertisements
Advertisements
प्रश्न
A burner raises the temperature of 360 g of water from 40°C to 100°C in 5 minutes. Calculate the rate of heat supplied by the burner.
Advertisements
उत्तर
m = 360 g = O .36 kg
Change in temperature, ΔT = (100 - 40)°C = 60°C = 60 K
Amount of heat required, Q = m x C x ΔT
= 0.36 x 4200 x 60 = 90720 J
Time taken = 5 min = 300 sec
Rate of heat supplied = `"Q"/"t" = 90720/300` = 302.4 J/s
APPEARS IN
संबंधित प्रश्न
What do you understand by the following statements:
The heat capacity of the body is 60JK-1.
Give three reasons for the increase of green house gases.
In Regnault's apparatus for measuring specific heat capacity of a solid, there is an inlet and an outlet in the steam chamber. The inlet is near the top and the outlet is near the bottom. Why is it better than the opposite choice where the inlet is near the bottom and the outlet is near the top?
Will the value of specific heat’capacity and specific latent heat of a substance change if the scale is °F instead of °C?
Read this activity and answer the following questions.
- Take three spheres of iron, copper and lead. the lead of equal mass.
- Put all the three spheres in boiling water in the beaker for some time.
- Take the three spheres out of the water.
- All the spheres will be at a temperature 100 °C.
- Put them immediately on the thick slab of wax.
- Note, the depth that each of the sphere goes into the wax.
Questions:
- Which property is determined from this activity?
- Give name to that property.
- Explain the term principal of heat exchange with the help of this activity.
Define specific heat capacity.
Express the change in internal energy in terms of molar specific heat capacity.
A piece of lead weighing 500 g gives out 1200 calories of heat when it is cooled from 100° C to 20° C. Find its specific heat.
An office room contains about 4000 moles of air. The change in the internal energy of this much air when it is cooled from 34° C to 19° C at a constant pressure of 1.0 atm is (Use `gamma_"air"` = 1.4 and Universal gas constant = 8.314 J / mol K) ____________.
