Advertisements
Advertisements
प्रश्न
A burner raises the temperature of 360 g of water from 40°C to 100°C in 5 minutes. Calculate the rate of heat supplied by the burner.
Advertisements
उत्तर
m = 360 g = O .36 kg
Change in temperature, ΔT = (100 - 40)°C = 60°C = 60 K
Amount of heat required, Q = m x C x ΔT
= 0.36 x 4200 x 60 = 90720 J
Time taken = 5 min = 300 sec
Rate of heat supplied = `"Q"/"t" = 90720/300` = 302.4 J/s
APPEARS IN
संबंधित प्रश्न
Calculate the mass of ice needed to cool 150 g of water contained in a calorimeter of mass 50 g at 32 °C such that the final temperature is 5 °C. Specific heat capacity of calorimeter = 0.4 J g-1 °C-1, Specific heat capacity of water = 4.2 J g-1°C-1, latent heat capacity of ice = 330 J g-1.
What do you understand by the following statements:
The heat capacity of the body is 60JK-1.
The temperature of 170 g of water at 50°C is lowered to 5°C by adding a certain amount of ice to it. Find the mass of ice added.
Given: Specific heat capacity of water = 4200 J kg-1 °C-1 and specific latent heat of ice = 336000 J kg-1.
It is generally cold after a hail-storm then during and before the hail storm. Give reason.
104g of water at 30°C is taken in a calorimeter made of copper of mass 42 g. When a certain mass of ice at 0°C is added to it, the final steady temperature of the mixture after the ice has melted, was found to be 10°C. Find the mass of ice added. [Specific heat capacity of water = 4.2 Jg–1°C–1 ; Specific latent heat of fusion of ice = 336 Jg–1; Specific heat capacity of copper = 0.4 Jg–1°C–1] .
State the condition for the flow of heat energy from one body to another.
Derive Mayer’s relation.
Which of the following substances (A, B and C) has the highest specific beat?
The specific heat capacity of water is ______.
