Advertisements
Advertisements
Question
A body of mass 3.5 kg displaces 1000 cm3 of water when fully immersed inside it. Calculate:
- the volume of body,
- the upthrust on body and
- the apparent weight of body in water.
Advertisements
Solution
Mass of body = 3.5 kg
Weight of the body = 3.5 kgf
Volume of water displaced when body is fully immersed = 1000 cm3
(i) Volume of body when fully immersed in liquid = Volume of water displaced
∴ Volume of body = 1000 cm3 or 0.001 m3
(ii) Upthrust on body = Volume of body × Density of water × g
= 0.001 × 1000 × g
= 1 kgf
(iii) Apparent weight = True weight - Upthrust
= 3.5 - 1
= 2.5 kgf
APPEARS IN
RELATED QUESTIONS
A body experiences the same buoyant force while floating in water or alcohol.
A body floats in a liquid when its weight becomes equal to the weight of the liquid displaced by its submerged part.
What is a density bottle? How is it used to find the density of a liquid?
Why does it happen?
A ship dips to a larger depth in fresh water as compared to marine water.
How does the pressure exerted by thrust depend on the area of surface on which it acts? Explain with a suitable example.
Complete the following sentence :
Pressure is .................... in all directions about a point in a liquid.
In what direction and at what point does the buoyant force on a body due to a liquid act?
The base of the cylindrical vessel measures 300 cm2. Water is poured into it up to a depth of 6 cm. Calculate the pressure of water on the base in the vessel.
What is meant by up thrust?
If the buoyant force is less, the object will float.
