Advertisements
Advertisements
प्रश्न
A body of mass 3.5 kg displaces 1000 cm3 of water when fully immersed inside it. Calculate:
- the volume of body,
- the upthrust on body and
- the apparent weight of body in water.
Advertisements
उत्तर
Mass of body = 3.5 kg
Weight of the body = 3.5 kgf
Volume of water displaced when body is fully immersed = 1000 cm3
(i) Volume of body when fully immersed in liquid = Volume of water displaced
∴ Volume of body = 1000 cm3 or 0.001 m3
(ii) Upthrust on body = Volume of body × Density of water × g
= 0.001 × 1000 × g
= 1 kgf
(iii) Apparent weight = True weight - Upthrust
= 3.5 - 1
= 2.5 kgf
APPEARS IN
संबंधित प्रश्न
Relative density of a substance is expressed in g cm-3.
What is the cause of buoyant force ?
A piece of wood floats on water. The buoyant force on wood will be
How does the pressure exerted by a solid and fluid differ?
The pressure inside a liquid of density p at a depth h is :
What do you understand by the term upthrust of a fluid? Describe an experiment to show its existence.
Describe an experiment to show that a body immersed in a liquid appears lighter than it really is.
It is easier to lift a heavy stone under water than in air. Explain.
Complete the following sentence.
Mass = .................... × density
What is meant by up thrust?
