Advertisements
Advertisements
प्रश्न
A body of mass 3.5 kg displaces 1000 cm3 of water when fully immersed inside it. Calculate:
- the volume of body,
- the upthrust on body and
- the apparent weight of body in water.
Advertisements
उत्तर
Mass of body = 3.5 kg
Weight of the body = 3.5 kgf
Volume of water displaced when body is fully immersed = 1000 cm3
(i) Volume of body when fully immersed in liquid = Volume of water displaced
∴ Volume of body = 1000 cm3 or 0.001 m3
(ii) Upthrust on body = Volume of body × Density of water × g
= 0.001 × 1000 × g
= 1 kgf
(iii) Apparent weight = True weight - Upthrust
= 3.5 - 1
= 2.5 kgf
APPEARS IN
संबंधित प्रश्न
What is the scientific name of the 'upward force' acting on an object immersed in a liquid?
Define buoyant force. Name two factors on which buoyant force depends.
What is the cause of buoyant force ?
How is the unit bar related to the S.I. unit pascal?
Pressure at the free surface of a water lake is P1, while at a point at depth h below its free surface is P2. (a) How are P1 and P2 related? (b)Which is more P1 or P2?
The pressure P1 at a certain depth in river water and P2 at the same depth in sea water are related as :
(i) The diameter of neck and bottom of a bottle are 2 cm and 10 cm, respectively. The bottle is completely filled with oil. If the cork in the neck is pressed in with a force of 1.2 kgf, what force is exerted on the bottom of the bottle?
(ii) Name the law/principle you have used to find the force in part (a).
Select the correct option.
Thrust acting perpendicularly on the unit surface area is called
Is thrust a scalar or vector quantity?
Complete the analogy.
Downward force : Weight :: Upward force offered by liquid : _____.
