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Question
`4x^2+4sqrt3x+3=0`
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Solution
`4x^2+4sqrt3x+3=0`
⇒` 4x^2+4sqrt3x=-3`
⇒`(2x)^2+2xx2x xxsqrt3+(sqrt3)^2=-3(sqrt3)^2` [Adding`( sqrt3)^2` on both sides]
⇒`(2x+sqrt3)^2=-3+3=0`
⇒`2x+sqrt3=0`
⇒`x=-sqrt3/2`
Hence,`-sqrt3/2` is the repeated root of the given equation.
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