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Question
Solve the following equation: c
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Solution
`2/"x"^2 - 5/"x" + 2 = 0`
2 - 5x + 2x2 = 0
2x2 - 5x+ 2= 0
`"x"^2 - 5/2 "x" + 1 = 0`
`"x"^2 - 2x - 1/2 "x" + 1 = 0`
`"x" ("x" - 2) - 1/2 ("x" - 2) = 0`
`("x" - 2)("x" - 1/2) = 0`
(x - 2) = 0 , `("x" - 1/2) = 0`
x = 2 , x = `1/2`
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