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`4x^2+4sqrt3x+3=0` - Mathematics

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प्रश्न

`4x^2+4sqrt3x+3=0` 

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उत्तर

`4x^2+4sqrt3x+3=0`  

⇒` 4x^2+4sqrt3x=-3` 

⇒`(2x)^2+2xx2x xxsqrt3+(sqrt3)^2=-3(sqrt3)^2`       [Adding`( sqrt3)^2` on both sides]

⇒`(2x+sqrt3)^2=-3+3=0` 

⇒`2x+sqrt3=0` 

⇒`x=-sqrt3/2` 

Hence,`-sqrt3/2` is the repeated root of the given equation.

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पाठ 10: Quadratic Equations - Exercises 2

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 10 Quadratic Equations
Exercises 2 | Q 4

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