Question

`4x^2+4sqrt3x+3=0` 

Answer 1

`4x^2+4sqrt3x+3=0`  

⇒` 4x^2+4sqrt3x=-3` 

⇒`(2x)^2+2xx2x xxsqrt3+(sqrt3)^2=-3(sqrt3)^2`       [Adding`( sqrt3)^2` on both sides]

⇒`(2x+sqrt3)^2=-3+3=0` 

⇒`2x+sqrt3=0` 

⇒`x=-sqrt3/2` 

Hence,`-sqrt3/2` is the repeated root of the given equation.