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Question
A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.
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Solution
et the cost price of article be Rs. x.
Then, gain percent = x
Therefore, the selling price of article
`=(x+x/100xx x)`
`=(x^2+100x)/100`
It is given that
`(x^2+100x)/100=24`
x2 + 100x = 2400
x2 + 100x - 2400 = 0
x2 + 120x - 20x - 2400 = 0
x(x + 120) - 20(x + 120) = 0
(x + 120)(x - 20) = 0
x + 120 = 0
x = -120
Or
x - 20 = 0
x = 20
Because x cannot be negative.
Thus, x = 20 is the require solution.
Therefore, the cost price of article be x = Rs. 20
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