Question

A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.

Answer 1

et the cost price of article be Rs. x.

Then, gain percent = x

Therefore, the selling price of article

`=(x+x/100xx x)`

`=(x^2+100x)/100`

It is given that

`(x^2+100x)/100=24`

x² + 100x = 2400

x² + 100x - 2400 = 0

x² + 120x - 20x - 2400 = 0

x(x + 120) - 20(x + 120) = 0

(x + 120)(x - 20) = 0

x + 120 = 0

x = -120

Or

x - 20 = 0

x = 20

Because x cannot be negative.

Thus, x = 20 is the require solution.

Therefore, the cost price of article be x = Rs. 20