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A Dealer Sells an Article for Rs. 24 and Gains as Much Percent as the Cost Price of the Article. Find the Cost Price of the Article. - Mathematics

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प्रश्न

A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.

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उत्तर

et the cost price of article be Rs. x.

Then, gain percent = x

Therefore, the selling price of article

`=(x+x/100xx x)`

`=(x^2+100x)/100`

It is given that

`(x^2+100x)/100=24`

x2 + 100x = 2400

x2 + 100x - 2400 = 0

x2 + 120x - 20x - 2400 = 0

x(x + 120) - 20(x + 120) = 0

(x + 120)(x - 20) = 0

x + 120 = 0

x = -120

Or

x - 20 = 0

x = 20

Because cannot be negative.

Thus, x = 20 is the require solution.

Therefore, the cost price of article be x = Rs. 20

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अध्याय 4: Quadratic Equations - Exercise 4.13 [पृष्ठ ८०]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 10
अध्याय 4 Quadratic Equations
Exercise 4.13 | Q 3 | पृष्ठ ८०

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