Advertisements
Advertisements
प्रश्न
A dealer sells an article for Rs. 24 and gains as much percent as the cost price of the article. Find the cost price of the article.
Advertisements
उत्तर
et the cost price of article be Rs. x.
Then, gain percent = x
Therefore, the selling price of article
`=(x+x/100xx x)`
`=(x^2+100x)/100`
It is given that
`(x^2+100x)/100=24`
x2 + 100x = 2400
x2 + 100x - 2400 = 0
x2 + 120x - 20x - 2400 = 0
x(x + 120) - 20(x + 120) = 0
(x + 120)(x - 20) = 0
x + 120 = 0
x = -120
Or
x - 20 = 0
x = 20
Because x cannot be negative.
Thus, x = 20 is the require solution.
Therefore, the cost price of article be x = Rs. 20
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation for x: x2 – 2ax – (4b2 – a2) = 0
The sum of two number a and b is 15, and the sum of their reciprocals `1/a` and `1/b` is 3/10. Find the numbers a and b.
The product of Shikha's age five years ago and her age 8 years later is 30, her age at both times being given in years. Find her present age.
The area of a right angled triangle is 165 m2. Determine its base and altitude if the latter exceeds the former by 7 m.
Solve the following quadratic equations by factorization:
`(3x-2)/(2x-3)=(3x-8)/(x+4)`
`x^2+8x-2=0`
`7x^2+3x-4=0`
Solve for x:
4x2 + 4bx − (a2 − b2) = 0
Solve the following quadratic equation by factorisation.
x2 – 15x + 54 = 0
Solve the following quadratic equations by factorization: \[2 x^2 + ax - a^2 = 0\]
If the equation x2 − bx + 1 = 0 does not possess real roots, then
Solve the following equation: `"m"/"n" "x"^2 + "n"/"m" = 1- 2"x"`
Solve the following equation :
`("x" - 1)/("x" - 2) + ("x" - 3)/("x" - 4) = 3 1/3`
A two digit positive number is such that the product of its digits is 6. If 9 is added to the number, the digits interchange their places. Find the number.
Solve the following by reducing them to quadratic form:
`sqrt(x^2 - 16) - (x - 4) = sqrt(x^2 - 5x + 4)`.
Solve the following equation by factorization
x2– 4x – 12 = 0,when x∈N
Find the values of x if p + 1 =0 and x2 + px – 6 = 0
Solve the following equation by factorisation :
x(x + 1) + (x + 2)(x + 3) = 42
A train, travelling at a uniform speed for 360 km, would have taken 48 minutes less to travel the same distance if its speed were 5 km/h more. Find the original speed of the train.
In the centre of a rectangular lawn of dimensions 50 m × 40 m, a rectangular pond has to be constructed so that the area of the grass surrounding the pond would be 1184 m2 [see figure]. Find the length and breadth of the pond.
