Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation by factorisation method:
`x/(x + 1) + (x + 1)/x = (34)/(15') x ≠ 0, x ≠ -1`
Advertisements
उत्तर
We have
`x/(x + 1) + (x + 1)/x = (34)/(15)`
⇒ `(x^2 + (x + 1)^2)/(x(x +1)) = (34)/(15)`
⇒ `(x^2 + x^2 + 1 + 2x)/(x^2 + x) = (34)/(15)`
⇒ `(2x^2 + 2x + 1)/(x2 + x) = (34)/(15)`
⇒ 34x2 + 34x = 30x2 + 30x + 15
⇒ 4x2 + 4x - 15 = 0
⇒ 4x2 + 10x - 6x - 15 = 0
⇒ 2x(2x + 5) -3(2x + 5) = 0
⇒ (2x + 5) (2x - 3) = 0
⇒ 2x + 5 = 0 or 2x - 3 = 0
⇒ 2x = -5 and 2x = 3
⇒ x = `-(5)/(2), x = (3)/(2)`.
संबंधित प्रश्न
The difference of squares of two numbers is 88. If the larger number is 5 less than twice the smaller number, then find the two numbers.
A piece of cloth costs Rs. 35. If the piece were 4 m longer and each meter costs Rs. 1 less, the cost would remain unchanged. How long is the piece?
The difference of two natural numbers is 5 and the difference of heir reciprocals is `5/14`Find the numbers
If ax2 + bx + c = 0 has equal roots, then c =
If x = 1 is a common roots of the equations ax2 + ax + 3 = 0 and x2 + x + b = 0, then ab =
Solve the following equation by factorization
(x – 3) (2x + 5) = 0
If the product of two positive consecutive even integers is 288, find the integers.
Two squares have sides A cm and (x + 4) cm. The sum of their areas is 656 sq. cm.Express this as an algebraic equation and solve it to find the sides of the squares.
Car A travels ‘x’ km for every litre of petrol, while car B travels (x + 5) km for every litre of petrol.
- Write down the number of litres of petrol used by car A and car B in covering a distance of 400 km.
- If car A uses 4 litres of petrol more than car B in covering 400 km. write down an equation, in A and solve it to determine the number of litres of petrol used by car B for the journey.
If x = –2 is the common solution of quadratic equations ax2 + x – 3a = 0 and x2 + bx + b = 0, then find the value of a2b.
