Advertisements
Advertisements
प्रश्न
Divide 57 into two parts whose product is 680.
Advertisements
उत्तर
Let the two parts be x and (57-x)
According to the given condition,
`x(57-x)=680`
⇒`57x-x^2=680`
⇒`x^2-57x+680=0`
⇒`x^2-40x-17x+680=0`
⇒`x(x-40)-17(x-40)=0`
⇒`(x-40) (x-17)=0`
⇒`x-40=0 or x-17=0`
⇒`x=40 or x=17`
When `x=40`
`57-x=57-40=17`
When` x=17`
`57-x=57-17=40`
Hence, the required parts are 17 and 40.
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
5x2 - 3x - 2 = 0
Solve the following quadratic equations by factorization:
`(x-1)/(x-2)+(x-3)/(x-4)=3 1/3`, x ≠ 2, 4
An aeroplane take 1 hour less for a journey of 1200 km if its speed is increased by 100 km/hr from its usual speed. Find its usual speed.
If two pipes function simultaneously, a reservoir will be filled in 12 hours. One pipe fills the reservoir 10 hours faster than the other. How many hours will the second pipe take to fill the reservoir?
A piece of cloth costs Rs. 35. If the piece were 4 m longer and each meter costs Rs. 1 less, the cost would remain unchanged. How long is the piece?
Solve the following quadratic equation by factorisation.
x2 – 15x + 54 = 0
Solve the following quadratic equations by factorization:
\[9 x^2 - 6 b^2 x - \left( a^4 - b^4 \right) = 0\]
Find the values of p for which the quadratic equation
If one root the equation 2x2 + kx + 4 = 0 is 2, then the other root is
The perimeter of the right angled triangle is 60cm. Its hypotenuse is 25cm. Find the area of the triangle.
A car covers a distance of 400 km at a certain speed. Had the speed been 12 km/hr more, the time taken for the journey would have been 1 hour 40 minutes less. Find the original speed of the car.
Solve the following by reducing them to quadratic equations:
`((7y - 1)/y)^2 - 3 ((7y - 1)/y) - 18 = 0, y ≠ 0`
Solve the following equation by factorization
`(1)/(7)(3x – 5)^2`= 28
Solve the following equation by factorization
`a/(ax - 1) + b/(bx - 1) = a + b, a + b ≠ 0, ab ≠ 0`
Find the values of x if p + 7 = 0, q – 12 = 0 and x2 + px + q = 0,
The difference between the squares of two numbers is 45. The square of the smaller number is 4 times the larger number. Determine the numbers.
The lengths of the parallel sides of a trapezium are (x + 9) cm and (2x – 3) cm and the distance between them is (x + 4) cm. If its area is 540 cm2, find x.
Solve the following equation by factorisation :
`sqrt(3x^2 - 2x - 1) = 2x - 2`
Car A travels ‘x’ km for every litre of petrol, while car B travels (x + 5) km for every litre of petrol.
- Write down the number of litres of petrol used by car A and car B in covering a distance of 400 km.
- If car A uses 4 litres of petrol more than car B in covering 400 km. write down an equation, in A and solve it to determine the number of litres of petrol used by car B for the journey.
A man spent Rs. 2800 on buying a number of plants priced at Rs x each. Because of the number involved, the supplier reduced the price of each plant by Rupee 1.The man finally paid Rs. 2730 and received 10 more plants. Find x.
