मराठी

Divide 57 into Two Parts Whose Product is 680.

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प्रश्न

Divide 57 into two parts whose product is 680. 

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उत्तर

Let the two parts be x and (57-x) 

According to the given condition, 

`x(57-x)=680` 

⇒`57x-x^2=680` 

⇒`x^2-57x+680=0` 

⇒`x^2-40x-17x+680=0`

⇒`x(x-40)-17(x-40)=0` 

⇒`(x-40) (x-17)=0` 

⇒`x-40=0  or  x-17=0` 

⇒`x=40  or  x=17` 

When `x=40` 

`57-x=57-40=17` 

When` x=17` 

`57-x=57-17=40` 

Hence, the required parts are 17 and 40. 

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पाठ 4: Quadratic Equations - Exercises 5

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आर. एस. अग्रवाल Mathematics [English] Class 10
पाठ 4 Quadratic Equations
Exercises 5 | Q 18

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