Advertisements
Advertisements
प्रश्न
Solve the following equation: a2b2x2 + b2x - a2x - 1 = 0
Advertisements
उत्तर
a2b2x2 + b2x - a2x - 1 = 0
b2 x(a2 x + 1)- 1(a2 x + 1) = 0
(a2 x + 1)(b2 x- 1) = 0
x = `-1/"a"^2` , x = `1/"b"^2`
APPEARS IN
संबंधित प्रश्न
Find two consecutive positive integers, sum of whose squares is 365.
The product of Ramu's age (in years) five years ago and his age (in years) nice years later is 15. Determine Ramu's present age.
Solve x2 – 4x – 12 =0; when x ∈ I
If a and b can take values 1, 2, 3, 4. Then the number of the equations of the form ax2 +bx + 1 = 0 having real roots is
A quadratic equation whose one root is 2 and the sum of whose roots is zero, is ______.
Solve the following equation : 5x2 - 11x + 2 = 0
The difference of the square of two natural numbers is 45. The square of the smaller number is 4 times the larger number. Determine the numbers.
The hypotenuse of a grassy land in the shape of a right triangle is 1 m more than twice the shortest side. If the third side is 7m more than the shortest side, find the sides of the grassy land.
The length of a rectangular garden is 12 m more than its breadth. The numerical value of its area is equal to 4 times the numerical value of its perimeter. Find the dimensions of the garden.
Forty years hence, Mr. Pratap’s age will be the square of what it was 32 years ago. Find his present age.
