Advertisements
Advertisements
प्रश्न
Solve the following equation :
`("x" - 1)/("x" - 2) + ("x" - 3)/("x" - 4) = 3 1/3`
Advertisements
उत्तर
`("x" - 1)/("x" - 2) + ("x" - 3)/("x" - 4) = 3 1/3`
`(("x" - 1)("x" - 4) + ("x" - 3)("x" - 2))/(("x" - 2)("x" - 4)) = 10/3`
`("x"^2 - 5"x" + 4 + "x"^2 - 5"x" + 6)/("x"^2 - 6"x" + 8) = 10/3`
`(2"x"^2 - 10"x" + 10)/("x"^2 - 6"x" + 8) = 10/3`
6x2 -30x+ 30 = 10x2 - 60x + 80
4x2 - 30x + 50 = 0
2x2 - 15x + 25 = 0
`"x"^2 - 15/2 "x" + 25/2 = 0`
`"x"^2 -5"x" - 5/2 "x" + 25/2 = 0`
`"x" ("x" - 5) - 5/2 ("x" - 5) = 0`
`("x" - 5)("x" - 5/2) = 0`
x = 5 , x = `5/2`
APPEARS IN
संबंधित प्रश्न
The product of Shikha's age five years ago and her age 8 years later is 30, her age at both times being given in years. Find her present age.
Solve the following quadratic equations by factorization: \[\frac{16}{x} - 1 = \frac{15}{x + 1}; x \neq 0, - 1\]
Is there any real value of 'a' for which the equation x2 + 2x + (a2 + 1) = 0 has real roots?
Solve the following equation: 4x2 + 4 bx - (a2 - b2) = 0
The sum of the square of two numbers is 233. If one of the numbers is 3 less than twice the other number. Find the numbers.
The product of a girl's age five years ago and her age 3 years later is 105. Find her present age.
A two digit number is such that the product of its digit is 14. When 45 is added to the number, then the digit interchange their places. Find the number.
Solve the following quadratic equation by factorisation:
x2 - 3x - 10 = 0
Solve the following equation by factorization
`(2)/(x^2) - (5)/x + 2 = 0, x ≠ 0`
The hypotenuse of grassy land in the shape of a right triangle is 1 metre more than twice the shortest side. If the third side is 7 metres more than the shortest side, find the sides of the grassy land.
