Advertisements
Advertisements
प्रश्न
Solve the following equation: abx2 +(b2-ac) x - bc = 0
Advertisements
उत्तर
abx2 +(b2-ac) x - bc = 0
abx2 +b2x - acx - bc = o
bx (ax+ b) - c(ax+ b) = o
(ax+b) (bx-c) = o
x = `- "b"/"a"` , x = `"c"/"b"`
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equations by factorization:
25x(x + 1) = -4
Solve : x2 – 11x – 12 =0; when x ∈ N
The sum of the squares of two consecutive positive even numbers is 452. Find the numbers.
Solve the following quadratic equation by factorisation.
x2 – 15x + 54 = 0
Find the value of k for which the following equations have real and equal roots:
\[\left( k + 1 \right) x^2 - 2\left( k - 1 \right)x + 1 = 0\]
Find the values of k for which the roots are real and equal in each of the following equation:
\[kx\left( x - 2\sqrt{5} \right) + 10 = 0\]
Solve the following equation: 4x2 + 4 bx - (a2 - b2) = 0
In each of the following, determine whether the given values are solution of the given equation or not:
2x2 - x + 9 = x2 + 4x + 3; x = 2, x = 3
Solve the following equation by factorization:
`x^2 - (1 + sqrt(2))x + sqrt(2) = 0`
If `x + 1/x = 2.5`, the value of x is ______.
