Advertisements
Advertisements
प्रश्न
Solve the following equation: abx2 +(b2-ac) x - bc = 0
Advertisements
उत्तर
abx2 +(b2-ac) x - bc = 0
abx2 +b2x - acx - bc = o
bx (ax+ b) - c(ax+ b) = o
(ax+b) (bx-c) = o
x = `- "b"/"a"` , x = `"c"/"b"`
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation by factorization method : `3x^2-29x+40=0`
Solve the following quadratic equations by factorization:
`1/((x-1)(x-2))+1/((x-2)(x-3))+1/((x-3)(x-4))=1/6`
Solve the following quadratic equations by factorization:
`100/x-100/(x+5)=1`
The sum of the squares of two consecutive positive even numbers is 452. Find the numbers.
Find the values of p for which the quadratic equation
Solve the following quadratic equation using factorization method:
`"x"^2-11"x"+24=0`
If an integer is added to its square the sum is 90. Find the integer with the help of a quadratic equation.
Solve the following equation and give your answer up to two decimal places:
x2 − 5x − 10 = 0
The length of a rectangle exceeds its breadth by 5 m. If the breadth were doubled and the length reduced by 9 m, the area of the rectangle would have increased by 140 m². Find its dimensions.
If x = 3 is one root of the quadratic equation 2x2 + px + 30 = 0, find the value of p and the other root of the quadratic equation.
