Advertisements
Advertisements
प्रश्न
Solve the following equation: abx2 +(b2-ac) x - bc = 0
Advertisements
उत्तर
abx2 +(b2-ac) x - bc = 0
abx2 +b2x - acx - bc = o
bx (ax+ b) - c(ax+ b) = o
(ax+b) (bx-c) = o
x = `- "b"/"a"` , x = `"c"/"b"`
APPEARS IN
संबंधित प्रश्न
John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.
If two pipes function simultaneously, a reservoir will be filled in 12 hours. One pipe fills the reservoir 10 hours faster than the other. How many hours will the second pipe take to fill the reservoir?
Solve the following quadratic equations by factorization:
`4/(x+2)-1/(x+3)=4/(2x+1)`
If one of the equation ax2 + bx + c = 0 is three times times the other, then b2 : ac =
The sum of the square of 2 consecutive odd positive integers is 290.Find them.
Find two consecutive positive even integers whose squares have the sum 340.
Solve (x2 + 3x)2 - (x2 + 3x) -6 = 0.
Find the values of x if p + 1 =0 and x2 + px – 6 = 0
Find three consecutive odd integers, the sum of whose squares is 83.
If twice the area of a smaller square is subtracted from the area of a larger square, the result is 14 cm2. However, if twice the area of the larger square is added to three times the area of the smaller square, the result is 203 cm2. Determine the sides of the two squares.
