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प्रश्न
Find the roots of the following quadratic equation by factorisation:
`2x^2 – x + 1/8 = 0`
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उत्तर
`2x^2 - x + 1/8 = 0`
⇒ 16x2 - 4x - 4x + 1 = 0
⇒ 4x(4x - 1) - 1(4x - 1) = 0
⇒ (4x - 1) (4x - 1) = 0
⇒ (4x - 1)2 = 0
⇒ 4x - 1 = 0
⇒ x = `1/4`
Thus, the required roots are `1/4, 1/4`.
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