Advertisements
Advertisements
प्रश्न
Some students planned a picnic. The budget for the food was Rs. 480. As eight of them failed to join the party, the cost of the food for each member increased by Rs. 10. Find how many students went for the picnic.
Some students planned a picnic. The budget for food was ₹ 480. But, eight of these failed to go and thus the cost of food for each member increased by ₹ 10. How many students attended the picnic?
Advertisements
उत्तर
Let x students planned a picnic.
Then, the share of each student `= 480/x`
According to question, 8 students fail to go picnic, then remaining students = (x − 8).
Therefore, new share of each student `480/(x-8)`
It is given that
`480/(x-8)-480/x=10`
`(480x-480(x-8))/(x(x-8))=10`
`(480x+3840-480)/(x^2-8x)=10`
`3840/(x^2-8x)=10`
`3840/10 = x^2 - 8x`
384 = x2 − 8x
x2 − 8x − 384 = 0
x2 + 16x − 24x − 384 = 0
x(x + 16) − 24(x + 16) = 0
(x + 16) (x − 24) = 0
x + 16 = 0
x = −16
Or
x − 24 = 0
x = 24
Because x cannot be negative.
Thus, the total numbers of students attend a picnic
= x − 8 = 24 − 8 = 16
Therefore, the total numbers of students attend a picnic be x = 16.
संबंधित प्रश्न
John and Jivanti together have 45 marbles. Both of them lost 5 marbles each, and the product of the number of marbles they now have is 124. We would like to find out how many marbles they had to start with.
A passenger train takes one hour less for a journey of 150 km if its speed is increased by 5 km/hr from its usual speed. Find the usual speed of the train.
Solve the following quadratic equation by
factorisation.
5m2 = 22m + 15
If the sum of the roots of the equation \[x^2 - \left( k + 6 \right)x + 2\left( 2k - 1 \right) = 0\] is equal to half of their product, then k =
An aeroplane travelled a distance of 400 km at an average speed of x km/hr. On the return journey the speed was increased by 40 km/hr. Write down the expression for the time taken for
the return Journey. If the return journey took 30 minutes less than the onward journey write down an equation in x and find its value.
Solve the following equation by factorization
3x2 – 5x – 12 = 0
Solve the following equation by factorization
`(8)/(x + 3) - (3)/(2 - x)` = 2
Solve the following equation by factorisation :
`sqrt(x + 15) = x + 3`
Complete the following activity to solve the given quadratic equation by factorization method.
Activity: x2 + 8x – 20 = 0
x2 + ( __ ) – 2x – 20 = 0
x (x + 10) – ( __ ) (x + 10) = 0
(x + 10) ( ____ ) = 0
x = ___ or x = 2
The polynomial equation x(x + 1) + 8 = (x + 2) (x – 2) is:
