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Solve: (a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0

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प्रश्न

Solve:

(a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0

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उत्तर

(a + b)2x2 – (a + b)x – 6 = 0; a + b ≠ 0

`=>` (a + b)2x2 – 3(a + b)x + 2(a + b)x – 6 = 0

`=>` (a + b)x [(a + b)x – 3] + 2[(a + b)x – 3] = 0

`=>` [(a + b)x – 3][(a + b)x – 2] = 0

`=>` (a + b)x – 3 = 0 or (a + b)x + 2 = 0

`=> x = 3/(a + b)` or `x = (-2)/(a + b)`

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अध्याय 5: Quadratic Equations - Exercise 5 (F) [पृष्ठ ६६]

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सेलिना Concise Mathematics [English] Class 10 ICSE
अध्याय 5 Quadratic Equations
Exercise 5 (F) | Q 13. | पृष्ठ ६६
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