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प्रश्न
Solve the following equation: 4x2 + 4 bx - (a2 - b2) = 0
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उत्तर
4x2 + 4 bx - (a2 - b2) = 0
`"x"^2 + "bx" - (("a"^2 - "b"^2))/4 = 0`
`"x"^2 + ("a + b")/2 xx -("a - b")/2 xx -("a"^2 - "b"^2)/4 = 0`
`"x" {"x" + ("a + b")/2} - "(a - b)"/2 {"x" + ("a + b")/2} = 0`
`{"x" + (("a + b"))/2} {"x" - (("a - b"))/2} = 0`
`{"x" + (("a + b"))/2} = 0 , {"x" - (("a - b"))/2} = 0`
`"x" = -(("a + b"))/2 , "x" = (("a - b"))/2`
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